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In fig. 6.2 bac 90° and ad  bc. then

WebIn the given figure, ∠BAC = 90 0 and AD⊥BC. Then, (a) BC.CD = BC 2 (b) AB.AC = BC 2 (c) BD.CD = AD 2 (d) AB.AC = AD 2 triangles class-10 1 Answer 0 votes answered Sep 4, 2024 by AmirMustafa (60.4k points) selected Sep 16, 2024 by Vikash Kumar Best answer (c) BD.CD = AD2 In ∆ BDA and ∆ADC, we have: WebIf deltaabc is an equilateral triangle such that ad perpendicular bc , then AD2 =… In Fig. 4.239, deltaahk is similar to deltaabc . If AK = 10 cm, BC = 3.5 cm and HK =…

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WebExample 5: In Fig. 6.3, PS is the bisector of ∠P and PQ = PR. Then ∆PRS and ∆PQS are congruent by the criterion (a) AAA (b) SAS (c) ASA (d) both (b) and (c) Fig. 6.3 Solution : Correct answer is (b). In examples 6 to 9, fill in the blanks to make the statements true. Example 6: The line segment joining a vertex of a triangle to the craft trappe en bois https://charlesandkim.com

In the given figure, ∠BAC = 90^0 and AD⊥BC. Then,

WebMar 7, 2024 · In the given figure, angle BAC = 90° and AD perpendicular BC. Then, A)BC.CD = BC² B)AB.AC =BC² C) BD.CD = AD² D)AB.AC = AD² Answer: Option C) BD.CD = AD² … WebApr 11, 2024 · In the given figure, if ∠BAC = 90° and AD⏊BC. Then, (A) BD.CD = AD2 (B) AB.AC = AD2 (C) BD.CD = AD2 (D) AB.AC = AD2 Ans: The correct option is (C): BD·CD = AD2 In ΔADB and ΔADC, It is given that ∠BDA = ∠ADC = 90° ∠B = ∠DAC = (90°- C) Now, by AA similarity criterion $\triangle \mathrm {ADB} \sim \triangle \mathrm {CDA}$ WebAug 15, 2024 · Choose the correct answer from the given four options:1.In Fig. 6.2, Z BAC = 90° and ADI BC. Then,ABDCFig. 6.2… Get the answers you need, now! panditdineshchandras panditdineshchandras 16.08.2024 Math Secondary School answered Choose the correct answer from the given four options: 1. crafttrans wolfsburg

In the given figure, if ∠ ADE = ∠ B, show that Δ ADE ∼Δ ABC. If AD …

Category:In Fig., \angle BAC=90^{o} and AD\perp BC. Then, (a) BD.CD=BC…

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In fig. 6.2 bac 90° and ad  bc. then

In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in …

WebAug 1, 2024 · Solution: The figure is attached below In Triangle ABC, angle BAC = 90 degree and AD is perpendicular to BC Given in the question a perpendicular is drawn AD on BC from angle BAC which is 90 degree So, these two triangles ABD and CAD are similar By Corresponding part of Similar Triangles (CPST), WebGiven, ABC is an equilateral triangle with AD as altitude. We have to find the value of 4AD². We know that in an equilateral triangle all the sides are of equal length. Let AB = BC = AC = x units ----- (1) Let AD = h units ----- (2) In an equilateral triangle, the altitude AD bisects BC. So, BD = CD = BC/2 = x/2

In fig. 6.2 bac 90° and ad  bc. then

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WebMar 22, 2024 · Transcript. Show More WebIn an equilateral triangle ABC (Fig. 6.2), AD is an altitude. Then 4AD² is equal to a. 2BD² b. BC² c. 3AB² d. 2DC². Solution: Given, ABC is an equilateral triangle with AD as altitude. We …

WebSolution In ΔADE and ΔABC, ∠A= ∠A (Common angle) ∠ADE= ∠B (Given) So by AA similarity, triangles are similar. So, by CPCT, AD AB= DE BC 3.8 3.6+2.1 = DE 4.2 DE = 3.8×4.2 5.7 = 2.8 Suggest Corrections 15 Similar questions Q. In the given figure, if ∠ADE = ∠B, AD = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm and BC = 4.2 cm, find DE. Q. WebMay 18, 2024 · In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in the figure is (A) 1 (B) 2 (C) 3 (D) 4 geometry class-6 1 Answer +1 vote answered May 18, 2024 by Varun01 (53.6k points) selected May 22, 2024 by Subnam01 (C) 3 We have, ∠BAC = 90° and AD ⊥ BC ∵ ∠BDA = ∠CDA = ∠BAC = 90° ∴ There are 3 right triangles formed in the given …

Web>> In figure, BAC = 90^o and AD BC . Then Question In figure, ∠BAC=90 o and AD⊥BC. Then A BD.CD=BC 2 B AB.AC=BC 2 C BD.CD=AD 2 D AB.AC=AD 2 Easy Solution Verified by … Webiii In Fig. 6.2,∠BAC=90∘and AD⊥. BC. Then, 4 Fig. 6.. Answer Answered By toppr How satisfied are you with the answer? This will help us to improve better answr Get Instant Solutions, 24x7 No Signup required download app More Questions by difficulty EASYMEDIUMHARD Prev QuestionNext Question Related Questions to study

WebIn Fig. 7.238, ∠BAC = 90° and AD ⊥ BC. Then, BD. CD = _________. Q. In figure, ∠BAC=90∘ and segment AD⊥BC. Prove that AD2 =BD×DC. [3 MARKS] Q. In the figure given below, …

WebIn Fig. 6.2, ∠BAC = 90° and AD BC. Then, a. BD . CD = BC 2 b. AB . AC = BC 2 c. BD . CD = AD 2 d. AB . AC = AD 2. Solution: Given, ∠BAC = 90° Also, AD BC. We know that a … dixon\\u0027s wholesale fisheriesWebAug 18, 2024 · In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, (A) BD . CD = BC 2 (B) AB . AC = BC 2 (C) BD . CD = AD 2 (D) AB . AC = AD 2 triangles ncert class-10 Please log in or … dixon\u0027s vacuum and sewing centerWebMay 18, 2024 · In Fig. 6.13, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is (a) 50° (b) 40° (c) 70° (d) 60° asked Aug 16, 2024 in Mathematics by AbhinavMehra ( 22.6k points) … dixon\u0027s wicked blueberry ginWebExample 5: In Fig. 6.3, PS is the bisector of ∠P and PQ = PR. Then ∆PRS and ∆PQS are congruent by the criterion (a) AAA (b) SAS (c) ASA (d) both (b) and (c) Fig. 6.3 Solution : … craft trapped chest minecraftWebQuestion In fig if ∠ADE=∠ABC ,then show that ADE∼ ABCand AD=6.8 cm, AE =8.6 cm, BE=2.4 cm and BC = 5.5 cm Find DE A 5.4 cm B 4.6 cm C 3.4 cm D None of these Medium Solution Verified by Toppr Correct option is C) Consider the diagram given in the question. ∠A is common in both the triangles, ADE and ABC. Also, ∠ADE=∠B dixon\u0027s violin safety harborWebExample 5 : Observe Fig. 6.30 and then find P. Fig. 6.30 Solution : In ABC and PQR, Rationalised 2024-24 92 MATHEMATICS. AB 3.8 1 , BC 6 1 CA 3 3 1 and RQ 7.6 2 QP 12 2 PR 6 3 2. AB BC CA That is, RQ QP PR craft treeWebMar 16, 2024 · Given: ABC is a triangle where ABC < 90 and AD BC To Prove: AC2 = AB2 + BC2 2BC.BD Proof: In right APB By Pythagoras Theorem, AB2 = AD2 + BD2 In right ADC By Pythagoras Theorem, AC2 = AD2 + CD2 From (2) AC2 = AD2 + CD2 AC2 = AD2 + (BC BD)2 AC2 = AD2 + BD2 + BC2 2BC.BD Putting AD2 + BD2 = AB2 from equation (1) AC2 = AB2 + … dixon\\u0027s wrecker service